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542 questions
A circuit consists of series combination of elements as resistance of 6 Ω, inductance of 0.4 H and a variable capacitor across 100 V, 50 Hz supply. Calculate
The given data are \(R=6\ \mathrm{\Omega}\), L=0.4H, capacitance is variable. Supply voltage is 100V
What is meant by hysteresis in a magnetic circuit? What is the significance of B-H curve?
The magnetization curve is useful to explain the magnetic properties of a ferromagnetic material like iron, cobalt and nikel. The magnetization curve is also called B-H curve or hysteresis loop which is a plot of internal magnetic flux density against external magnetic field.
Determine the value R in Fig. 15(a) such that 4 Ω resistor consumes maximum power.
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Fig. 15(a)
\(R_1=\frac{3\times R}{3+R+3}=\frac{3R}{6+R}\) \(R_2=\frac{3\times3}{3+R+3}=\frac{9}{6+R}\)
An iron ring of mean length 50 cm, has an air – gap of 1 mm and winding of 200 turns. The relative permeability of iron is 300. When 1A current follows through the coil, determine flux density.
Given that The mean length of the iron ring l=50 cm=0.5 m
A coil of resistance 10 Ω and inductance 0.02 Hs connected in series with another coil of resistance 6 Ω and inductance 15 mH across a 230 V, 50 Hz supply. calculate
The circuit diagram of question 6(b) is given in Fig. 27. Total impedance for coil 1 is \(Z_1=\left(10+j\times2\pi\times50\times0.02\right)=(10+j6.282)\ \mathrm{\Omega}\)
A flux of 0.0006Wb is required in the air – gap of an iron ring of cross – section 5.0 cm2and mean length 2.7 m with an air – gap of 4.5 mm. Determine the ampere turns required. Six H values and corresponding B values are noted from the magnetization curve of iron and given below.
H(At/m) |
200 |
400 |
500 |
600 |
800 |
1000 |
B(Wb/m2) |
0.4 |
0.8 |
1.0 |
1.09 |
1.17 |
1.19 |
Given that, Flux=0.0006 Wb Cross section area \(A=5\ {cm}^2=5\times{10}^{-4}m^2\)
A 20 Ω resistor, a choke coil having some inductance and some resistance and a capacitor are connected in series across a 25 V variable frequency source. When frequency is 400 Hz, the current is maximum and its value is 0.5 Amp and the potential difference across the capacitor is 150 V. Calculate the resistance and the inductance of the chokes coil and the capacitance of the capacitor.
The total impedance of the circuit is \(R_{eq}=20+R+j\omega L-\frac{1}{\omega C}\) The maximum current is following through the circuit at the time of resonance. For the resonance \(X_L\) and \(X_C\) is same.
State Ampere’s Circular law.
Ampere’s circular law states that the line integral of the tangential component of the magnetic field around a closed path is equal to the current enclosed by the path.
Two coils have self inductance \(L_{1}\) and \(L_{2}\) and mutual inductance between them is M. Derive a mathematical expression for co – efficient of coupling (k) for these coils. Find an expression for the energy stored in a magnetic field.
The above inductor having inductance L is connected to the bettery through key K. In this case inducted e.m.f is given by \(e=-L\frac{dL}{dt}\) …(1)
State and explain Biot – Savart law.
This law was deduced from a number of experiments on the effect of current carrying conductor on permanent magnets such as the compass needle experiment of oersted.
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