Basic Electrical Engineering

36 questions and answers

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The galvanometer shown in the circuit has a resistance of 5 Ω. Find the current through the galvanometer using Thevenin’s theorem.

Fig.22(a)

Equivalent resistance of the circuit \(R_{th}=\frac{10\times15}{10+15}+\frac{12\times16}{12+16}=6+6.86=12.86\ \mathrm{\Omega}\)

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added 2 years ago
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Derive an expression for the resonant frequency of a parallel circuit, one branch consisting of a coil of inductance L and resistance R and the other branch of capacitance C.

The series RL circuit with parallel C is given in Fig. 19. The designed circuit consists of resistance R, inductance L are in series with parallel configuration of capacitance C. Let us consider the current I flowing through the RLC circuit by the a.c. voltage source with constant value of V.

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added 2 years ago
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Explain

  • Star – delta conversion
  • Delta – star conversion with the help of a purely resistive circuit

In this transformation any resistance in delta network can be found out if the resistances of corresponding star network are known. Here the branch resistances in the star connections are

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added 2 years ago
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Find the current in each branch of the network using Kirchhoff’s law

Fig.23

Applying KVL in mesh I, II and II respectively \(-2I_1-3I_2+{7I}_3=12\) … (1)

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added 2 years ago